#1996
Scrieţi un program care citeşte cheia de codificare şi un text codificat şi determină mesajul decodificat.
Problema | zigzag | Operații I/O |
![]() zigzag.in /zigzag.out
|
---|---|---|---|
Limita timp | 0.1 secunde | Limita memorie |
Total: 2 MB
/
Stivă 1 MB
|
Id soluție | #57313875 | Utilizator | |
Fișier | zigzag.cpp | Dimensiune | 1.47 KB |
Data încărcării | 25 Martie 2025, 16:26 | Scor / rezultat | Eroare de compilare |
zigzag.cpp: In function 'int main()': zigzag.cpp:12:28: error: expected ']' before '}' token char m[10*c+10][2*m2+10}; ^ zigzag.cpp:9:15: warning: unused variable 'i' [-Wunused-variable] int c, n, i, j, m2, k, nr1, nr2, poz, g; ^ zigzag.cpp:9:18: warning: unused variable 'j' [-Wunused-variable] int c, n, i, j, m2, k, nr1, nr2, poz, g; ^ zigzag.cpp:9:25: warning: unused variable 'k' [-Wunused-variable] int c, n, i, j, m2, k, nr1, nr2, poz, g; ^ zigzag.cpp:9:28: warning: unused variable 'nr1' [-Wunused-variable] int c, n, i, j, m2, k, nr1, nr2, poz, g; ^ zigzag.cpp:9:33: warning: unused variable 'nr2' [-Wunused-variable] int c, n, i, j, m2, k, nr1, nr2, poz, g; ^ zigzag.cpp:9:38: warning: unused variable 'poz' [-Wunused-variable] int c, n, i, j, m2, k, nr1, nr2, poz, g; ^ zigzag.cpp:9:43: warning: unused variable 'g' [-Wunused-variable] int c, n, i, j, m2, k, nr1, nr2, poz, g; ^ zigzag.cpp: At global scope: zigzag.cpp:13:5: error: expected unqualified-id before 'for' for(i=0;i<=10*c+9;i++){ ^ zigzag.cpp:13:13: error: 'i' does not name a type for(i=0;i<=10*c+9;i++){ ^ zigzag.cpp:13:23: error: 'i' does not name a type for(i=0;i<=10*c+9;i++){ ^ zigzag.cpp:18:5: error: 'k' does not name a type k=c*2-2; ^ zigzag.cpp:19:5: error: 'nr1' does not name a type nr1=n/k; ^ zigzag.cpp:20:5: error: 'poz' does not name a type poz=n%k; ^ zigzag.cpp:21:5: error: 'nr2' does not name a type nr2=nr1*2; ^ zigzag.cpp:22:5: error: 'fin' does not name a type fin.get(); ^ zigzag.cpp:23:5: error: 'g' does not name a type g=0; ^ zigzag.cpp:24:5: error: expected unqualified-id before 'if' if(poz!=0){ ^ zigzag.cpp:27:5: error: expected unqualified-id before 'for' for(i=0;i<nr1+g;i++){ ^ zigzag.cpp:27:13: error: 'i' does not name a type for(i=0;i<nr1+g;i++){ ^ zigzag.cpp:27:21: error: 'i' does not name a type for(i=0;i<nr1+g;i++){ ^ zigzag.cpp:31:5: error: 'cout' does not name a type cout<<'\n'; ^ zigzag.cpp:32:5: error: expected unqualified-id before 'for' for(i=1;i<c-1;i++){ ^ zigzag.cpp:32:13: error: 'i' does not name a type for(i=1;i<c-1;i++){ ^ zigzag.cpp:32:19: error: 'i' does not name a type for(i=1;i<c-1;i++){ ^ zigzag.cpp:46:5: error: 'g' does not name a type g=0; ^ zigzag.cpp:47:5: error: expected unqualified-id before 'if' if(poz>=c){ ^ zigzag.cpp:50:5: error: expected unqualified-id before 'for' for(i=0;i<nr1+g;i++){ ^ zigzag.cpp:50:13: error: 'i' does not name a type for(i=0;i<nr1+g;i++){ ^ zigzag.cpp:50:21: error: 'i' does not name a type for(i=0;i<nr1+g;i++){ ^ zigzag.cpp:54:5: error: 'cout' does not name a type cout<<'\n'; ^ zigzag.cpp:55:5: error: expected unqualified-id before 'for' for(i=0;i<=10*c+4;i++){ ^ zigzag.cpp:55:13: error: 'i' does not name a type for(i=0;i<=10*c+4;i++){ ^ zigzag.cpp:55:23: error: 'i' does not name a type for(i=0;i<=10*c+4;i++){ ^ zigzag.cpp:73:5: error: expected unqualified-id before 'return' return 0; ^ zigzag.cpp:74:1: error: expected declaration before '}' token } ^
www.pbinfo.ro permite evaluarea a două tipuri de probleme:
Problema zigzag face parte din prima categorie. Soluția propusă de tine va fi evaluată astfel:
Suma punctajelor acordate pe testele utilizate pentru verificare este 100. Astfel, soluția ta poate obține cel mult 100 de puncte, caz în care se poate considera corectă.