#86
Să se scrie un program care ordonează crescător elementele din prima jumătate a unui vector și descrescător elementele din a doua jumătate.
| Problema | HalfSort | Operații I/O |
halfsort.in/halfsort.out
|
|---|---|---|---|
| Limita timp | 0.1 secunde | Limita memorie |
Total: 64 MB
/
Stivă 8 MB
|
| Id soluție | #64691238 | Utilizator | |
| Fișier | halfsort.cpp | Dimensiune | 525 B |
| Data încărcării | 23 Mai 2026, 15:20 | Scor/rezultat | Eroare de compilare |
halfsort.cpp:5:13: error: variable ‘std::ifstream cin’ has initializer but incomplete type 5 | ifstream cin("halfsort.in"); | ^ halfsort.cpp:6:14: error: variable ‘std::ofstream cout’ has initializer but incomplete type 6 | ofstream cout("halfsort.out"); | ^ halfsort.cpp: In function ‘int main()’: halfsort.cpp:10:5: error: reference to ‘cin’ is ambiguous 10 | cin>>n; | ^~~ In file included from halfsort.cpp:1: /usr/include/c++/13/iostream:62:18: note: candidates are: ‘std::istream std::cin’ 62 | extern istream cin; ///< Linked to standard input | ^~~ halfsort.cpp:5:10: note: ‘<typeprefixerror>cin’ 5 | ifstream cin("halfsort.in"); | ^~~ halfsort.cpp:13:9: error: reference to ‘cin’ is ambiguous 13 | cin>>a[i]; | ^~~ /usr/include/c++/13/iostream:62:18: note: candidates are: ‘std::istream std::cin’ 62 | extern istream cin; ///< Linked to standard input | ^~~ halfsort.cpp:5:10: note: ‘<typeprefixerror>cin’ 5 | ifstream cin("halfsort.in"); | ^~~ halfsort.cpp:23:9: error: reference to ‘cout’ is ambiguous 23 | cout<<a[i]<<" "; | ^~~~ /usr/include/c++/13/iostream:63:18: note: candidates are: ‘std::ostream std::cout’ 63 | extern ostream cout; ///< Linked to standard output | ^~~~ halfsort.cpp:6:10: note: ‘<typeprefixerror>cout’ 6 | ofstream cout("halfsort.out"); | ^~~~
www.pbinfo.ro permite evaluarea a două tipuri de probleme:
Problema HalfSort face parte din prima categorie. Soluția propusă de tine va fi evaluată astfel:
Suma punctajelor acordate pe testele utilizate pentru verificare este 100. Astfel, soluția ta poate obține cel mult 100 de puncte, caz în care se poate considera corectă.