#779
Se dă o matrice cu n linii şi m coloane şi elemente numere naturale. Să se determine câte elemente din matrice au toți vecinii numere pare.
| Problema | VeciniPari | Operații I/O |
tastatură/ecran
|
|---|---|---|---|
| Limita timp | 0.1 secunde | Limita memorie |
Total: 64 MB
/
Stivă 8 MB
|
| Id soluție | #64623450 | Utilizator | |
| Fișier | vecinipari.cpp | Dimensiune | 474 B |
| Data încărcării | 19 Mai 2026, 09:40 | Scor/rezultat | Eroare de compilare |
vecinipari.cpp: In function ‘int main()’: vecinipari.cpp:9:6: warning: this ‘for’ clause does not guard... [-Wmisleading-indentation] 9 | {for(int j=0;j<m;j++) | ^~~ vecinipari.cpp:11:9: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the ‘for’ 11 | if(i>0 && a[i-1][j]%2!=0)ok=0; | ^~ vecinipari.cpp:10:13: warning: unused variable ‘ok’ [-Wunused-variable] 10 | int ok=1; | ^~ vecinipari.cpp:11:26: error: ‘j’ was not declared in this scope 11 | if(i>0 && a[i-1][j]%2!=0)ok=0; | ^ vecinipari.cpp:11:34: error: ‘ok’ was not declared in this scope 11 | if(i>0 && a[i-1][j]%2!=0)ok=0; | ^~ vecinipari.cpp:12:32: error: ‘j’ was not declared in this scope 12 | if(i<n-1 && a[i+1][j]%2!=0)ok=0; | ^ vecinipari.cpp:12:40: error: ‘ok’ was not declared in this scope 12 | if(i<n-1 && a[i+1][j]%2!=0)ok=0; | ^~ vecinipari.cpp:13:16: error: ‘j’ was not declared in this scope 13 | if(j>0 && a[i][j-1]%2!=0)ok=0; | ^ vecinipari.cpp:13:38: error: ‘ok’ was not declared in this scope 13 | if(j>0 && a[i][j-1]%2!=0)ok=0; | ^~ vecinipari.cpp:14:16: error: ‘j’ was not declared in this scope 14 | if(j<m-1 && a[i][j+1]%2!=0)ok=0; | ^ vecinipari.cpp:14:40: error: ‘ok’ was not declared in this scope 14 | if(j<m-1 && a[i][j+1]%2!=0)ok=0; | ^~ vecinipari.cpp:15:16: error: ‘ok’ was not declared in this scope 15 | if(ok==1)c++; | ^~
www.pbinfo.ro permite evaluarea a două tipuri de probleme:
Problema VeciniPari face parte din prima categorie. Soluția propusă de tine va fi evaluată astfel:
Suma punctajelor acordate pe testele utilizate pentru verificare este 100. Astfel, soluția ta poate obține cel mult 100 de puncte, caz în care se poate considera corectă.