Rezumat problemă

permutari_11

#4491

Se citește un număr natural impar n (n<10). Afișați în ordine lexicografică toate permutările mulțimii {1,2,…,n} în care n se află în mijlocul permutării.

Consola Muresan Ciprian (mcip1977) Ciprian Muresan ușoară

Clasa 11 Backtracking Elemente de combinatorică

Rezolvă

Detalii

Problema	permutari_11	Operații I/O	tastatură/ecran
Limita timp	0.3 secunde	Limita memorie	Total: 64 MB / Stivă 8 MB
Id soluție	#64267862	Utilizator	Raileanu Sofia (RaileanuSofia)
Fișier	permutari_11.cpp	Dimensiune	603 B
Data încărcării	27 Aprilie 2026, 11:28	Scor/rezultat	100 puncte

Evaluare

Mesaj compilare

permutari_11.cpp: In function ‘int valid(int)’:
permutari_11.cpp:9:9: warning: this ‘if’ clause does not guard... [-Wmisleading-indentation]
    9 |         if(v[i]==v[k])return 0;return 1;
      |         ^~
permutari_11.cpp:9:32: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the ‘if’
    9 |         if(v[i]==v[k])return 0;return 1;
      |                                ^~~~~~
permutari_11.cpp:8:5: warning: this ‘for’ clause does not guard... [-Wmisleading-indentation]
    8 |     for(i=1;i<=k-1;i++)
      |     ^~~
permutari_11.cpp:9:32: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the ‘for’
    9 |         if(v[i]==v[k])return 0;return 1;
      |                                ^~~~~~
permutari_11.cpp: In function ‘int solutie(int)’:
permutari_11.cpp:13:5: warning: this ‘if’ clause does not guard... [-Wmisleading-indentation]
   13 |     if(k==n)
      |     ^~
permutari_11.cpp:14:18: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the ‘if’
   14 |         return 1;return 0;
      |                  ^~~~~~
permutari_11.cpp: In function ‘void afisare(int)’:
permutari_11.cpp:19:5: warning: this ‘for’ clause does not guard... [-Wmisleading-indentation]
   19 |     for(i=1;i<=k;i++)cout<<v[i]<<' ';cout<<'\n';
      |     ^~~
permutari_11.cpp:19:38: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the ‘for’
   19 |     for(i=1;i<=k;i++)cout<<v[i]<<' ';cout<<'\n';
      |                                      ^~~~
permutari_11.cpp: In function ‘void backt(int)’:
permutari_11.cpp:28:11: warning: suggest explicit braces to avoid ambiguous ‘else’ [-Wdangling-else]
   28 |         if(valid(k)==1)
      |           ^

Rezultat evaluare

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