Rezumat problemă

Suma Divizori

#376

Se citește un număr natural n. Să se determine suma divizorilor săi.

Consola Candale Silviu (silviu) ușoară

Clasa 9 Algoritmi elementari Divizibilitate Determinarea divizorilor

Rezolvă

Detalii

Problema	Suma Divizori	Operații I/O	tastatură/ecran
Limita timp	0.1 secunde	Limita memorie	Total: 64 MB / Stivă 8 MB
Id soluție	#64140812	Utilizator	Talaban Ioan (IoanTLB)
Fișier	suma_divizori.cpp	Dimensiune	224 B
Data încărcării	20 Aprilie 2026, 10:14	Scor/rezultat	Eroare de compilare

Evaluare

Mesaj compilare

suma_divizori.cpp:1:1: error: ‘include’ does not name a type
    1 | include <iostream>
      | ^~~~~~~
suma_divizori.cpp: In function ‘int main()’:
suma_divizori.cpp:6:28: warning: range-based ‘for’ loops with initializer only available with ‘-std=c++20’ or ‘-std=gnu++20’ [-Wc++20-extensions]
    6 |         for (long long i=1;i*i<=n:i++)
      |                            ^
suma_divizori.cpp:6:34: error: found ‘:’ in nested-name-specifier, expected ‘::’
    6 |         for (long long i=1;i*i<=n:i++)
      |                                  ^
      |                                  ::
suma_divizori.cpp:6:33: error: ‘n’ is not a class, namespace, or enumeration
    6 |         for (long long i=1;i*i<=n:i++)
      |                                 ^
suma_divizori.cpp:13:1: error: ‘cout’ was not declared in this scope
   13 | cout<<s;
      | ^~~~
suma_divizori.cpp:13:7: error: ‘s’ was not declared in this scope
   13 | cout<<s;
      |       ^
suma_divizori.cpp:14:1: error: expected primary-expression before ‘return’
   14 | return 0:
      | ^~~~~~
suma_divizori.cpp:13:9: error: expected ‘)’ before ‘return’
   13 | cout<<s;
      |         ^
      |         )
   14 | return 0:
      | ~~~~~~   
suma_divizori.cpp:6:13: note: to match this ‘(’
    6 |         for (long long i=1;i*i<=n:i++)
      |             ^
suma_divizori.cpp:14:9: error: expected ‘;’ before ‘:’ token
   14 | return 0:
      |         ^
      |         ;
suma_divizori.cpp:6:9: warning: this ‘for’ clause does not guard... [-Wmisleading-indentation]
    6 |         for (long long i=1;i*i<=n:i++)
      |         ^~~
suma_divizori.cpp:14:9: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the ‘for’
   14 | return 0:
      |         ^
suma_divizori.cpp:14:9: error: expected primary-expression before ‘:’ token
suma_divizori.cpp:5:15: warning: unused variable ‘n’ [-Wunused-variable]
    5 |     long long n;
      |               ^

Cum funcționează evaluarea?